What are the solutions to the equation x(x+15)=1924 ?

The solutions to the equation x(x+15)=1924 are x=37,x=-52

Find the zeros of x(x+15)=1924

The zeros of x(x+15)=1924 are x=37,x=-52

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x (x + 15) = 1924

x = 37, x = - 52

Solution steps

x (x + 15) = 1924

Expand

x (x + 15) : x^{2} + 15 x

x^{2} + 15 x = 1924

Move

1924

to the left side

x^{2} + 15 x - 1924 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot ( - 1924 )}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot (- 1924) = 89

x_{1, 2} = \frac{- 15 \pm 89}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 89}{2 \cdot 1}, x_{2} = \frac{- 15 - 89}{2 \cdot 1}

x = \frac{- 15 + 89}{2 \cdot 1} : 37

x = \frac{- 15 - 89}{2 \cdot 1} : - 52

The solutions to the quadratic equation are:

x = 37, x = - 52

x, x^{2} + y^{2} + 2 x y - 7 x - 6 y + 10 = 0

15 x^{2} + 5 x - 6 = 0

2 x (x + 2) + 2 x (x + 1) = x^{2} + 4

\frac{x ^{2}}{4} - \frac{3 x}{2} + 2 = 0

x^{2} + 7 x - 24 = 5 x

What are the solutions to the equation x(x+15)=1924 ?
The solutions to the equation x(x+15)=1924 are x=37,x=-52
Find the zeros of x(x+15)=1924
The zeros of x(x+15)=1924 are x=37,x=-52