What are the solutions to the equation m^2+16=0 ?

The solutions to the equation m^2+16=0 are m=4i,m=-4i

Find the zeros of m^2+16=0

The zeros of m^2+16=0 are m=4i,m=-4i

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m^{2} + 16 = 0

m = 4 i, m = - 4 i

Solution steps

m^{2} + 16 = 0

Move

16

to the right side

m^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 16, m = - - 16

- 16 = 4 i

- - 16 = - 4 i

m = 4 i, m = - 4 i

x > - 5 or x < - 2

x^{2} + 8 x y - 9 y^{2}

9 x^{2} - 4 x + 2 = 0

\frac{x}{2} \geq \frac{8}{x + 1} + 7

- 5.5 - 3 y - 6.7 - y = - 3 y + 8.1

What are the solutions to the equation m^2+16=0 ?
The solutions to the equation m^2+16=0 are m=4i,m=-4i
Find the zeros of m^2+16=0
The zeros of m^2+16=0 are m=4i,m=-4i