What are the solutions to the equation 9x^2+12x-3=0 ?

The solutions to the equation 9x^2+12x-3=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

Find the zeros of 9x^2+12x-3=0

The zeros of 9x^2+12x-3=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

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9 x^{2} + 12 x - 3 = 0

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

Decimal Notation

x = 0.21525 \dots, x = - 1.54858 \dots

Solution steps

9 x^{2} + 12 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 ( - 3 )}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 (- 3) = 67

x_{1, 2} = \frac{- 12 \pm 6 7}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 12 + 6 7}{2 \cdot 9}, x_{2} = \frac{- 12 - 6 7}{2 \cdot 9}

x = \frac{- 12 + 6 7}{2 \cdot 9} : \frac{- 2 + 7}{3}

x = \frac{- 12 - 6 7}{2 \cdot 9} : - \frac{2 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

x^{2} - 2 \cdot x - 1 = 0

- 3 x^{2} = - 6 x - 3

(x - 3) (x + 7) = - 24

x^{2} + 4 x - 76 = 0

2 x^{2} = 7 x + 10

What are the solutions to the equation 9x^2+12x-3=0 ?
The solutions to the equation 9x^2+12x-3=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3
Find the zeros of 9x^2+12x-3=0
The zeros of 9x^2+12x-3=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3