What are the solutions to the equation -0.25x^2+3x-6.29=0 ?

The solutions to the equation -0.25x^2+3x-6.29=0 are x=(30-sqrt(271))/5 ,x=(30+sqrt(271))/5

Find the zeros of -0.25x^2+3x-6.29=0

The zeros of -0.25x^2+3x-6.29=0 are x=(30-sqrt(271))/5 ,x=(30+sqrt(271))/5

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- 0.25 x^{2} + 3 x - 6.29 = 0

x = \frac{30 - 271}{5}, x = \frac{30 + 271}{5}

Decimal Notation

x = 2.70758 \dots, x = 9.29241 \dots

Solution steps

- 0.25 x^{2} + 3 x - 6.29 = 0

Multiply both sides by

100

- 25 x^{2} + 300 x - 629 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 300 \pm 30 0 ^{2} - 4 ( - 25 ) ( - 629 )}{2 ( - 25 )}

30 0^{2} - 4 (- 25) (- 629) = 10271

x_{1, 2} = \frac{- 300 \pm 10 271}{2 ( - 25 )}

Separate the solutions

x_{1} = \frac{- 300 + 10 271}{2 ( - 25 )}, x_{2} = \frac{- 300 - 10 271}{2 ( - 25 )}

x = \frac{- 300 + 10 271}{2 ( - 25 )} : \frac{30 - 271}{5}

x = \frac{- 300 - 10 271}{2 ( - 25 )} : \frac{30 + 271}{5}

The solutions to the quadratic equation are:

x = \frac{30 - 271}{5}, x = \frac{30 + 271}{5}

De = (5 \cdot p - x) \cdot \frac{5 \cdot p - x}{p} - 2 \cdot \frac{( 5 \cdot p - x )}{p}

(x - 7) (x - 2) = 0

2 y^{2} - 7 y = 10

1 - 4 x^{2} = - 8

21 - 6 x^{2} = 11 x

What are the solutions to the equation -0.25x^2+3x-6.29=0 ?
The solutions to the equation -0.25x^2+3x-6.29=0 are x=(30-sqrt(271))/5 ,x=(30+sqrt(271))/5
Find the zeros of -0.25x^2+3x-6.29=0
The zeros of -0.25x^2+3x-6.29=0 are x=(30-sqrt(271))/5 ,x=(30+sqrt(271))/5