What are the solutions to the equation 5m^2+m=120 ?

The solutions to the equation 5m^2+m=120 are m= 24/5 ,m=-5

Find the zeros of 5m^2+m=120

The zeros of 5m^2+m=120 are m= 24/5 ,m=-5

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5 m^{2} + m = 120

m = \frac{24}{5}, m = - 5

Decimal Notation

m = 4.8, m = - 5

Solution steps

5 m^{2} + m = 120

Move

120

to the left side

5 m^{2} + m - 120 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 120 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 120) = 49

m_{1, 2} = \frac{- 1 \pm 49}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- 1 + 49}{2 \cdot 5}, m_{2} = \frac{- 1 - 49}{2 \cdot 5}

m = \frac{- 1 + 49}{2 \cdot 5} : \frac{24}{5}

m = \frac{- 1 - 49}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

m = \frac{24}{5}, m = - 5

x^{2} + 21 x + 19 = 10 x - 5

10 x^{2} + 13 x - 3 = 0

- 0.5 q^{2} + 620 = 30 q + 270

- 6 x^{2} + 18 x + 60 = 0

2 X^{2} - (- 10) = - X

What are the solutions to the equation 5m^2+m=120 ?
The solutions to the equation 5m^2+m=120 are m= 24/5 ,m=-5
Find the zeros of 5m^2+m=120
The zeros of 5m^2+m=120 are m= 24/5 ,m=-5