What are the solutions to the equation 4x^2-27x-7=0 ?

The solutions to the equation 4x^2-27x-7=0 are x=7,x=-1/4

Find the zeros of 4x^2-27x-7=0

The zeros of 4x^2-27x-7=0 are x=7,x=-1/4

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4 x^{2} - 27 x - 7 = 0

x = 7, x = - \frac{1}{4}

Decimal Notation

x = 7, x = - 0.25

Solution steps

4 x^{2} - 27 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 27)^{2} - 4 \cdot 4 (- 7) = 29

x_{1, 2} = \frac{- ( - 27 ) \pm 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 29}{2 \cdot 4}, x_{2} = \frac{- ( - 27 ) - 29}{2 \cdot 4}

x = \frac{- ( - 27 ) + 29}{2 \cdot 4} : 7

x = \frac{- ( - 27 ) - 29}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 7, x = - \frac{1}{4}

lo g_{3} (\frac{1}{3}) = x

0. 6^{5}

(\frac{( 4 x ^{- 2} ) ^{- 2}}{( 4 x ) ^{3}})^{3}

18 a + 36

\frac{3}{2} (x - \frac{4}{5}) = - \frac{87}{10}

What are the solutions to the equation 4x^2-27x-7=0 ?
The solutions to the equation 4x^2-27x-7=0 are x=7,x=-1/4
Find the zeros of 4x^2-27x-7=0
The zeros of 4x^2-27x-7=0 are x=7,x=-1/4