What are the solutions to the equation 7x^2+8x+6=0 ?

The solutions to the equation 7x^2+8x+6=0 are x=-4/7+i(sqrt(26))/7 ,x=-4/7-i(sqrt(26))/7

Find the zeros of 7x^2+8x+6=0

The zeros of 7x^2+8x+6=0 are x=-4/7+i(sqrt(26))/7 ,x=-4/7-i(sqrt(26))/7

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7 x^{2} + 8 x + 6 = 0

x = - \frac{4}{7} + i \frac{26}{7}, x = - \frac{4}{7} - i \frac{26}{7}

Solution steps

7 x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 7 \cdot 6}{2 \cdot 7}

Simplify

8^{2} - 4 \cdot 7 \cdot 6 : 226 i

x_{1, 2} = \frac{- 8 \pm 2 26 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 8 + 2 26 i}{2 \cdot 7}, x_{2} = \frac{- 8 - 2 26 i}{2 \cdot 7}

x = \frac{- 8 + 2 26 i}{2 \cdot 7} : - \frac{4}{7} + i \frac{26}{7}

x = \frac{- 8 - 2 26 i}{2 \cdot 7} : - \frac{4}{7} - i \frac{26}{7}

The solutions to the quadratic equation are:

x = - \frac{4}{7} + i \frac{26}{7}, x = - \frac{4}{7} - i \frac{26}{7}

a^{2} - 13 a + 40 = 0

x (x + 2) = x (4 - x)

0 = - 2 x^{2} + 18 x

2 x^{2} - 2 x + 7 = 5

x, 5 x^{2} + 3 x y + 2 y^{2} - x + 3 y + 6 = 0

What are the solutions to the equation 7x^2+8x+6=0 ?
The solutions to the equation 7x^2+8x+6=0 are x=-4/7+i(sqrt(26))/7 ,x=-4/7-i(sqrt(26))/7
Find the zeros of 7x^2+8x+6=0
The zeros of 7x^2+8x+6=0 are x=-4/7+i(sqrt(26))/7 ,x=-4/7-i(sqrt(26))/7