What are the solutions to the equation 5x^2+23x=2x-4 ?

The solutions to the equation 5x^2+23x=2x-4 are x=-1/5 ,x=-4

Find the zeros of 5x^2+23x=2x-4

The zeros of 5x^2+23x=2x-4 are x=-1/5 ,x=-4

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5 x^{2} + 23 x = 2 x - 4

x = - \frac{1}{5}, x = - 4

Decimal Notation

x = - 0.2, x = - 4

Solution steps

5 x^{2} + 23 x = 2 x - 4

Move

4

to the left side

5 x^{2} + 23 x + 4 = 2 x

Move

2 x

to the left side

5 x^{2} + 21 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

2 1^{2} - 4 \cdot 5 \cdot 4 = 19

x_{1, 2} = \frac{- 21 \pm 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 21 + 19}{2 \cdot 5}, x_{2} = \frac{- 21 - 19}{2 \cdot 5}

x = \frac{- 21 + 19}{2 \cdot 5} : - \frac{1}{5}

x = \frac{- 21 - 19}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - 4

x, x^{2} y^{2} = 2

r^{2} + 8 r + 784 = 0

4 x^{2} - 11 = 53

7 x + 450 = x^{2}

(2 x - 3)^{2} - (x + 3)^{2} = x^{2}

What are the solutions to the equation 5x^2+23x=2x-4 ?
The solutions to the equation 5x^2+23x=2x-4 are x=-1/5 ,x=-4
Find the zeros of 5x^2+23x=2x-4
The zeros of 5x^2+23x=2x-4 are x=-1/5 ,x=-4