What are the solutions to the equation -0.03x^2-35x+712=0 ?

The solutions to the equation -0.03x^2-35x+712=0 are x=-3560/3 ,x=20

Find the zeros of -0.03x^2-35x+712=0

The zeros of -0.03x^2-35x+712=0 are x=-3560/3 ,x=20

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- 0.03 x^{2} - 35 x + 712 = 0

x = - \frac{3560}{3}, x = 20

Decimal Notation

x = - 1186.66666 \dots, x = 20

Solution steps

- 0.03 x^{2} - 35 x + 712 = 0

Multiply both sides by

100

- 3 x^{2} - 3500 x + 71200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3500 ) \pm ( - 3500 ) ^{2} - 4 ( - 3 ) \cdot 71200}{2 ( - 3 )}

(- 3500)^{2} - 4 (- 3) \cdot 71200 = 3620

x_{1, 2} = \frac{- ( - 3500 ) \pm 3620}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 3500 ) + 3620}{2 ( - 3 )}, x_{2} = \frac{- ( - 3500 ) - 3620}{2 ( - 3 )}

x = \frac{- ( - 3500 ) + 3620}{2 ( - 3 )} : - \frac{3560}{3}

x = \frac{- ( - 3500 ) - 3620}{2 ( - 3 )} : 20

The solutions to the quadratic equation are:

x = - \frac{3560}{3}, x = 20

y^{2} - 3 y - 28 = 0

x, (x - 1) (3 x + 2 y - 1) = C

x^{2} - 4 x + 5 = 0

x (x + 8) = 3

6 x^{2} + x (\frac{5 - 2 x}{3}) + 3 x - 9 = 0

What are the solutions to the equation -0.03x^2-35x+712=0 ?
The solutions to the equation -0.03x^2-35x+712=0 are x=-3560/3 ,x=20
Find the zeros of -0.03x^2-35x+712=0
The zeros of -0.03x^2-35x+712=0 are x=-3560/3 ,x=20