What are the solutions to the equation -3x^2+18x-27=0 ?

The solutions to the equation -3x^2+18x-27=0 are x=3

Find the zeros of -3x^2+18x-27=0

The zeros of -3x^2+18x-27=0 are x=3

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- 3 x^{2} + 18 x - 27 = 0

x = 3

Solution steps

- 3 x^{2} + 18 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 3 ) ( - 27 )}{2 ( - 3 )}

1 8^{2} - 4 (- 3) (- 27) = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 ( - 3 )}

x = \frac{- 18}{2 ( - 3 )}

\frac{- 18}{2 ( - 3 )} = 3

x = 3

The solution to the quadratic equation is:

x = 3

3 x^{2} = 5 x - 3

(x^{1} + x^{2}) = 5

x^{2} + 10 x - 144 = 0

2 x^{2} + 7 x = - 5

y, x = y^{2} - 2 y

What are the solutions to the equation -3x^2+18x-27=0 ?
The solutions to the equation -3x^2+18x-27=0 are x=3
Find the zeros of -3x^2+18x-27=0
The zeros of -3x^2+18x-27=0 are x=3