What are the solutions to the equation 6x^2+23x+7=0 ?

The solutions to the equation 6x^2+23x+7=0 are x=-1/3 ,x=-7/2

Find the zeros of 6x^2+23x+7=0

The zeros of 6x^2+23x+7=0 are x=-1/3 ,x=-7/2

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6 x^{2} + 23 x + 7 = 0

x = - \frac{1}{3}, x = - \frac{7}{2}

Decimal Notation

x = - 0.33333 \dots, x = - 3.5

Solution steps

6 x^{2} + 23 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

2 3^{2} - 4 \cdot 6 \cdot 7 = 19

x_{1, 2} = \frac{- 23 \pm 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 23 + 19}{2 \cdot 6}, x_{2} = \frac{- 23 - 19}{2 \cdot 6}

x = \frac{- 23 + 19}{2 \cdot 6} : - \frac{1}{3}

x = \frac{- 23 - 19}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{7}{2}

2 x^{2} = 3 x - 5

y, x^{3} - 4 x y - y^{2} = 3

13 x^{2} - 5 x = 0

y, x = y^{2} - 3 y + 2

\frac{x ^{2}}{4} = 25

What are the solutions to the equation 6x^2+23x+7=0 ?
The solutions to the equation 6x^2+23x+7=0 are x=-1/3 ,x=-7/2
Find the zeros of 6x^2+23x+7=0
The zeros of 6x^2+23x+7=0 are x=-1/3 ,x=-7/2