What are the solutions to the equation solvefor x,x^2+(s+t)x+st=0 ?

The solutions to the equation solvefor x,x^2+(s+t)x+st=0 are x=-t,x=-s

Find the zeros of solvefor x,x^2+(s+t)x+st=0

The zeros of solvefor x,x^2+(s+t)x+st=0 are x=-t,x=-s

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} + (s + t) x + s t = 0

x = - t, x = - s

Solution steps

x^{2} + (s + t) x + s t = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( s + t ) \pm ( s + t ) ^{2} - 4 \cdot 1 \cdot s t}{2 \cdot 1}

Simplify

(s + t)^{2} - 4 \cdot 1 \cdot s t : s - t

x_{1, 2} = \frac{- ( s + t ) \pm ( s - t )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( s + t ) + s - t}{2 \cdot 1}, x_{2} = \frac{- ( s + t ) - ( s - t )}{2 \cdot 1}

x = \frac{- ( s + t ) + s - t}{2 \cdot 1} : - t

x = \frac{- ( s + t ) - ( s - t )}{2 \cdot 1} : - s

The solutions to the quadratic equation are:

x = - t, x = - s

x^{2} - 6 x + 5 = 12

x^{2} - 6 x + 5 = - 8

x^{2} + 2 x - 2 = 0

5 0^{2} = x^{2} + x^{2}

3 y - 0.03 y^{2} = 0

What are the solutions to the equation solvefor x,x^2+(s+t)x+st=0 ?
The solutions to the equation solvefor x,x^2+(s+t)x+st=0 are x=-t,x=-s
Find the zeros of solvefor x,x^2+(s+t)x+st=0
The zeros of solvefor x,x^2+(s+t)x+st=0 are x=-t,x=-s