What are the solutions to the equation (3-x)(2-x)-2=0 ?

The solutions to the equation (3-x)(2-x)-2=0 are x=4,x=1

Find the zeros of (3-x)(2-x)-2=0

The zeros of (3-x)(2-x)-2=0 are x=4,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 - x) (2 - x) - 2 = 0

x = 4, x = 1

Solution steps

(3 - x) (2 - x) - 2 = 0

Expand

(3 - x) (2 - x) - 2 : x^{2} - 5 x + 4

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

m = (x + 7) 2 + (x - 10) (x - 4)

200 = 10 t + \frac{1}{2} \cdot 2 t^{2}

12 x^{2} - 8 x - 15 = 0

1^{2} + 2^{2} + 3^{2} + n^{2} = (3.14) (n + 1) (2 n + 1)

a^{2} - 4 a - 4 = 0

What are the solutions to the equation (3-x)(2-x)-2=0 ?
The solutions to the equation (3-x)(2-x)-2=0 are x=4,x=1
Find the zeros of (3-x)(2-x)-2=0
The zeros of (3-x)(2-x)-2=0 are x=4,x=1