What are the solutions to the equation -x^2-2x=-47 ?

The solutions to the equation -x^2-2x=-47 are x=-1-4sqrt(3),x=4sqrt(3)-1

Find the zeros of -x^2-2x=-47

The zeros of -x^2-2x=-47 are x=-1-4sqrt(3),x=4sqrt(3)-1

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- x^{2} - 2 x = - 47

x = - 1 - 43, x = 43 - 1

Decimal Notation

x = - 7.92820 \dots, x = 5.92820 \dots

Solution steps

- x^{2} - 2 x = - 47

Move

47

to the left side

- x^{2} - 2 x + 47 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 47}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 47 = 83

x_{1, 2} = \frac{- ( - 2 ) \pm 8 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 8 3}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 8 3}{2 ( - 1 )} : - 1 - 43

x = \frac{- ( - 2 ) - 8 3}{2 ( - 1 )} : 43 - 1

The solutions to the quadratic equation are:

x = - 1 - 43, x = 43 - 1

x^{2} + 10 x + 169 = 0

x^{2} - 14 x + 20

2 x^{2} - 13 x + 7 = x^{2}

2 x^{2} + 3 x = 70

2 x^{2} - 4 x - 126 = 0

What are the solutions to the equation -x^2-2x=-47 ?
The solutions to the equation -x^2-2x=-47 are x=-1-4sqrt(3),x=4sqrt(3)-1
Find the zeros of -x^2-2x=-47
The zeros of -x^2-2x=-47 are x=-1-4sqrt(3),x=4sqrt(3)-1