What are the solutions to the equation -3x^2+15x=0 ?

The solutions to the equation -3x^2+15x=0 are x=0,x=5

Find the zeros of -3x^2+15x=0

The zeros of -3x^2+15x=0 are x=0,x=5

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- 3 x^{2} + 15 x = 0

x = 0, x = 5

Solution steps

- 3 x^{2} + 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

1 5^{2} - 4 (- 3) \cdot 0 = 15

x_{1, 2} = \frac{- 15 \pm 15}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 15 + 15}{2 ( - 3 )}, x_{2} = \frac{- 15 - 15}{2 ( - 3 )}

x = \frac{- 15 + 15}{2 ( - 3 )} : 0

x = \frac{- 15 - 15}{2 ( - 3 )} : 5

The solutions to the quadratic equation are:

x = 0, x = 5

\frac{x ^{2}}{25 + 9} = 13

4 x^{2} = - 4

x, 4 x^{2} - y^{2} + 4 z = 0

x, x^{2} + 2 x y - 3 y^{2} = 0

2 x^{2} - 15 x = 0

What are the solutions to the equation -3x^2+15x=0 ?
The solutions to the equation -3x^2+15x=0 are x=0,x=5
Find the zeros of -3x^2+15x=0
The zeros of -3x^2+15x=0 are x=0,x=5