What are the solutions to the equation x(x+1)=600 ?

The solutions to the equation x(x+1)=600 are x=24,x=-25

Find the zeros of x(x+1)=600

The zeros of x(x+1)=600 are x=24,x=-25

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x (x + 1) = 600

x = 24, x = - 25

Solution steps

x (x + 1) = 600

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 600

Move

600

to the left side

x^{2} + x - 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 600 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 600) = 49

x_{1, 2} = \frac{- 1 \pm 49}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 49}{2 \cdot 1}, x_{2} = \frac{- 1 - 49}{2 \cdot 1}

x = \frac{- 1 + 49}{2 \cdot 1} : 24

x = \frac{- 1 - 49}{2 \cdot 1} : - 25

The solutions to the quadratic equation are:

x = 24, x = - 25

(x) = - 3 (x - 2)^{2} + 4

6 x^{2} - 24 x = 0

x^{2} = 8 x + 105

14 x^{2} - 4 = x

x, \frac{- x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

What are the solutions to the equation x(x+1)=600 ?
The solutions to the equation x(x+1)=600 are x=24,x=-25
Find the zeros of x(x+1)=600
The zeros of x(x+1)=600 are x=24,x=-25