What are the solutions to the equation m^2+m-5/16 =0 ?

The solutions to the equation m^2+m-5/16 =0 are m= 1/4 ,m=-5/4

Find the zeros of m^2+m-5/16 =0

The zeros of m^2+m-5/16 =0 are m= 1/4 ,m=-5/4

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m^{2} + m - \frac{5}{16} = 0

m = \frac{1}{4}, m = - \frac{5}{4}

Decimal Notation

m = 0.25, m = - 1.25

Solution steps

m^{2} + m - \frac{5}{16} = 0

Multiply both sides by

16

16 m^{2} + 16 m - 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 16 ( - 5 )}{2 \cdot 16}

1 6^{2} - 4 \cdot 16 (- 5) = 24

m_{1, 2} = \frac{- 16 \pm 24}{2 \cdot 16}

Separate the solutions

m_{1} = \frac{- 16 + 24}{2 \cdot 16}, m_{2} = \frac{- 16 - 24}{2 \cdot 16}

m = \frac{- 16 + 24}{2 \cdot 16} : \frac{1}{4}

m = \frac{- 16 - 24}{2 \cdot 16} : - \frac{5}{4}

The solutions to the quadratic equation are:

m = \frac{1}{4}, m = - \frac{5}{4}

\frac{\frac{( 16 xx )}{2}}{3} = \frac{7}{16000}

x, y (x^{2} + 2 x + 1) + 2 x^{2} + 4 x = (x + 2)^{2}

m^{2} - 14 m - 20 = 0

(3 - 2 x)^{2} - 4 (6 - x) + 3 x = - 9

3 x^{2} + 4 x^{2} = 6 x + 9

What are the solutions to the equation m^2+m-5/16 =0 ?
The solutions to the equation m^2+m-5/16 =0 are m= 1/4 ,m=-5/4
Find the zeros of m^2+m-5/16 =0
The zeros of m^2+m-5/16 =0 are m= 1/4 ,m=-5/4