What are the solutions to the equation λ^2+12λ=59 ?

The solutions to the equation λ^2+12λ=59 are λ=-6+sqrt(95),λ=-6-sqrt(95)

Find the zeros of λ^2+12λ=59

The zeros of λ^2+12λ=59 are λ=-6+sqrt(95),λ=-6-sqrt(95)

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λ^{2} + 12 λ = 59

λ = - 6 + 95, λ = - 6 - 95

Decimal Notation

λ = 3.74679 \dots, λ = - 15.74679 \dots

Solution steps

λ^{2} + 12 λ = 59

Move

59

to the left side

λ^{2} + 12 λ - 59 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 59 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 59) = 295

λ_{1, 2} = \frac{- 12 \pm 2 95}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- 12 + 2 95}{2 \cdot 1}, λ_{2} = \frac{- 12 - 2 95}{2 \cdot 1}

λ = \frac{- 12 + 2 95}{2 \cdot 1} : - 6 + 95

λ = \frac{- 12 - 2 95}{2 \cdot 1} : - 6 - 95

The solutions to the quadratic equation are:

λ = - 6 + 95, λ = - 6 - 95

\frac{6.43 - x}{500} = 0.0061 (x - 0.994)^{2}

m^{2} - 5 m + 1 = 0

3 x^{2} - 3 x + 0.5 = 0

16 x^{2} + 16 x + 2 = 34

x (5 x - 2) = 0

What are the solutions to the equation λ^2+12λ=59 ?
The solutions to the equation λ^2+12λ=59 are λ=-6+sqrt(95),λ=-6-sqrt(95)
Find the zeros of λ^2+12λ=59
The zeros of λ^2+12λ=59 are λ=-6+sqrt(95),λ=-6-sqrt(95)