What are the solutions to the equation u^2-u-1=0 ?

The solutions to the equation u^2-u-1=0 are u=(1+sqrt(5))/2 ,u=(1-sqrt(5))/2

Find the zeros of u^2-u-1=0

The zeros of u^2-u-1=0 are u=(1+sqrt(5))/2 ,u=(1-sqrt(5))/2

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u^{2} - u - 1 = 0

u = \frac{1 + 5}{2}, u = \frac{1 - 5}{2}

Decimal Notation

u = 1.61803 \dots, u = - 0.61803 \dots

Solution steps

u^{2} - u - 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 1) = 5

u_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, u_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

u = \frac{- ( - 1 ) + 5}{2 \cdot 1} : \frac{1 + 5}{2}

u = \frac{- ( - 1 ) - 5}{2 \cdot 1} : \frac{1 - 5}{2}

The solutions to the quadratic equation are:

u = \frac{1 + 5}{2}, u = \frac{1 - 5}{2}

x, z = 3 x^{2} - x y + 2 y^{2} - 4 x - 7 y + 12

(x - 7) (x - 6) = 0

112 = - 16 t^{2} + 128 t

6 d^{2} - 3 d - 4 = d^{2}

3 = 20 \cdot \frac{2}{2} \cdot t - \frac{1}{2} \cdot 9.8 \cdot t^{2}

What are the solutions to the equation u^2-u-1=0 ?
The solutions to the equation u^2-u-1=0 are u=(1+sqrt(5))/2 ,u=(1-sqrt(5))/2
Find the zeros of u^2-u-1=0
The zeros of u^2-u-1=0 are u=(1+sqrt(5))/2 ,u=(1-sqrt(5))/2