What are the solutions to the equation (x-1)^2-2=0 ?

The solutions to the equation (x-1)^2-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1

Find the zeros of (x-1)^2-2=0

The zeros of (x-1)^2-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1

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(x - 1)^{2} - 2 = 0

x = 2 + 1, x = - 2 + 1

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

(x - 1)^{2} - 2 = 0

Move

2

to the right side

(x - 1)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 2 : x = 2 + 1

Solve

x - 1 = - 2 : x = - 2 + 1

The solutions to the quadratic equation are:

x = 2 + 1, x = - 2 + 1

- 3 x^{2} + 48 x = 0

1 = \frac{x ^{2}}{2} + 4

- 8 x = 2 x^{2}

0 = - 4.9 t^{2} + 25 t

(x - 0.2)^{2} = 0.64

What are the solutions to the equation (x-1)^2-2=0 ?
The solutions to the equation (x-1)^2-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1
Find the zeros of (x-1)^2-2=0
The zeros of (x-1)^2-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1