What are the solutions to the equation (3x-1)^2=108 ?

The solutions to the equation (3x-1)^2=108 are x=(6sqrt(3)+1)/3 ,x=(-6sqrt(3)+1)/3

Find the zeros of (3x-1)^2=108

The zeros of (3x-1)^2=108 are x=(6sqrt(3)+1)/3 ,x=(-6sqrt(3)+1)/3

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(3 x - 1)^{2} = 108

x = \frac{6 3 + 1}{3}, x = \frac{- 6 3 + 1}{3}

Decimal Notation

x = 3.79743 \dots, x = - 3.13076 \dots

Solution steps

(3 x - 1)^{2} = 108

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 108 : x = \frac{6 3 + 1}{3}

Solve

3 x - 1 = - 108 : x = \frac{- 6 3 + 1}{3}

The solutions to the quadratic equation are:

x = \frac{6 3 + 1}{3}, x = \frac{- 6 3 + 1}{3}

z^{2} - 4 z + 1 = 0

x, x^{2} + 4 x + 8 = - 2 y^{2}

2 a^{2} = 1

(x + 6) (x - 4) = 0

x (2 x + 1) = 3 x (- 2 x - 1) - 3 (x^{2} + x + 1)

What are the solutions to the equation (3x-1)^2=108 ?
The solutions to the equation (3x-1)^2=108 are x=(6sqrt(3)+1)/3 ,x=(-6sqrt(3)+1)/3
Find the zeros of (3x-1)^2=108
The zeros of (3x-1)^2=108 are x=(6sqrt(3)+1)/3 ,x=(-6sqrt(3)+1)/3