What are the solutions to the equation (x-2)^2-10=26 ?

The solutions to the equation (x-2)^2-10=26 are x=8,x=-4

Find the zeros of (x-2)^2-10=26

The zeros of (x-2)^2-10=26 are x=8,x=-4

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(x - 2)^{2} - 10 = 26

x = 8, x = - 4

Solution steps

(x - 2)^{2} - 10 = 26

Move

10

to the right side

(x - 2)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 36 : x = 8

Solve

x - 2 = - 36 : x = - 4

The solutions to the quadratic equation are:

x = 8, x = - 4

(x^{2} - 4 x + 1) = 0

6 x^{2} = 8 x

x, z = - 3 x^{2} + y^{2} + 6 x - 8 y

x, s x (x) - x (0^{-}) 3 x (s) = 4 \frac{1}{( s ^{1} )}

(3 x - 2)^{2} = \frac{1}{4}

What are the solutions to the equation (x-2)^2-10=26 ?
The solutions to the equation (x-2)^2-10=26 are x=8,x=-4
Find the zeros of (x-2)^2-10=26
The zeros of (x-2)^2-10=26 are x=8,x=-4