What are the solutions to the equation 7y=3y^2+2 ?

The solutions to the equation 7y=3y^2+2 are y=2,y= 1/3

Find the zeros of 7y=3y^2+2

The zeros of 7y=3y^2+2 are y=2,y= 1/3

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7 y = 3 y^{2} + 2

y = 2, y = \frac{1}{3}

Solution steps

7 y = 3 y^{2} + 2

Switch sides

3 y^{2} + 2 = 7 y

Move

7 y

to the left side

3 y^{2} + 2 - 7 y = 0

Write in the standard form

a x^{2} + b x + c = 0

3 y^{2} - 7 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 2 = 5

y_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 3}, y_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 3}

y = \frac{- ( - 7 ) + 5}{2 \cdot 3} : 2

y = \frac{- ( - 7 ) - 5}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

y = 2, y = \frac{1}{3}

6^{2} + 7^{2}

(x - 5) (x + 6) = 0

24 a^{2} b m^{2} - 36 b^{2} m^{4}

5 x (x - 7) = 0

y^{2} = 16

What are the solutions to the equation 7y=3y^2+2 ?
The solutions to the equation 7y=3y^2+2 are y=2,y= 1/3
Find the zeros of 7y=3y^2+2
The zeros of 7y=3y^2+2 are y=2,y= 1/3