What are the solutions to the equation (k^2)/2+k=-1/2 ?

The solutions to the equation (k^2)/2+k=-1/2 are k=-1

Find the zeros of (k^2)/2+k=-1/2

The zeros of (k^2)/2+k=-1/2 are k=-1

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\frac{k ^{2}}{2} + k = - \frac{1}{2}

k = - 1

Solution steps

\frac{k ^{2}}{2} + k = - \frac{1}{2}

Multiply both sides by

2

k^{2} + 2 k = - 1

Move

1

to the left side

k^{2} + 2 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

k_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

k = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

k = - 1

The solution to the quadratic equation is:

k = - 1

2 x^{2} + 8 x = 0

15 x^{2} - 45 x - 60 = 0

c^{2} = 13

t, s = \frac{1}{5} g t^{2}

y, x^{4} + y^{2} - x y = 16

What are the solutions to the equation (k^2)/2+k=-1/2 ?
The solutions to the equation (k^2)/2+k=-1/2 are k=-1
Find the zeros of (k^2)/2+k=-1/2
The zeros of (k^2)/2+k=-1/2 are k=-1