What are the solutions to the equation solvefor y,y^2=cx^4+3x ?

The solutions to the equation solvefor y,y^2=cx^4+3x are y=sqrt(cx^4+3x),y=-sqrt(cx^4+3x)

Find the zeros of solvefor y,y^2=cx^4+3x

The zeros of solvefor y,y^2=cx^4+3x are y=sqrt(cx^4+3x),y=-sqrt(cx^4+3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y, y^{2} = c x^{4} + 3 x

y = c x^{4} + 3 x, y = - c x^{4} + 3 x

Solution steps

y^{2} = c x^{4} + 3 x

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = c x^{4} + 3 x, y = - c x^{4} + 3 x

3 (x - 7)^{2} = 12

λ^{2} - λ - 12 = 0

x \cdot x = 0

x^{2} + x - 2 x = 0

(4 x + 5) (7 x - 6) = 0

What are the solutions to the equation solvefor y,y^2=cx^4+3x ?
The solutions to the equation solvefor y,y^2=cx^4+3x are y=sqrt(cx^4+3x),y=-sqrt(cx^4+3x)
Find the zeros of solvefor y,y^2=cx^4+3x
The zeros of solvefor y,y^2=cx^4+3x are y=sqrt(cx^4+3x),y=-sqrt(cx^4+3x)