What are the solutions to the equation k^2=25 ?

The solutions to the equation k^2=25 are k=5,k=-5

Find the zeros of k^2=25

The zeros of k^2=25 are k=5,k=-5

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k^{2} = 25

k = 5, k = - 5

Solution steps

k^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 25, k = - 25

25 = 5

- 25 = - 5

k = 5, k = - 5

x^{2} + (\frac{2}{3})^{2} = 1

\frac{( x + 1 ) ^{2}}{4} = 9

y, x y^{2} + 3 x^{2} y = 3 x^{4}

x, I n x = x^{2} - 2

x^{2} - x + 1 = 0

What are the solutions to the equation k^2=25 ?
The solutions to the equation k^2=25 are k=5,k=-5
Find the zeros of k^2=25
The zeros of k^2=25 are k=5,k=-5