What are the solutions to the equation solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9 ?

The solutions to the equation solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9 are m=-isqrt(A),m=isqrt(A)

Find the zeros of solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9

The zeros of solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9 are m=-isqrt(A),m=isqrt(A)

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solve for

m, A = 3 (m + 3)^{2} - 4 (m - 3)^{2} - 42 m + 9

m = - i A, m = i A

Solution steps

A = 3 (m + 3)^{2} - 4 (m - 3)^{2} - 42 m + 9

Expand

3 (m + 3)^{2} - 4 (m - 3)^{2} - 42 m + 9 : - m^{2}

A = - m^{2}

Switch sides

- m^{2} = A

Move

A

to the left side

- m^{2} - A = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 ( - 1 ) ( - A )}{2 ( - 1 )}

Simplify

0^{2} - 4 (- 1) (- A) : 2 i A

m_{1, 2} = \frac{- 0 \pm 2 i A}{2 ( - 1 )}

Separate the solutions

m_{1} = \frac{- 0 + 2 i A}{2 ( - 1 )}, m_{2} = \frac{- 0 - 2 i A}{2 ( - 1 )}

m = \frac{- 0 + 2 i A}{2 ( - 1 )} : - i A

m = \frac{- 0 - 2 i A}{2 ( - 1 )} : i A

The solutions to the quadratic equation are:

m = - i A, m = i A

0 = 12 x^{2} - 18 x + 6

2 4^{2} = x^{2} + x^{2}

2 x^{2} - 16 x + 64 = 0

x^{2} - 63 = - 2

(p + 6)^{2} = 25

What are the solutions to the equation solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9 ?
The solutions to the equation solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9 are m=-isqrt(A),m=isqrt(A)
Find the zeros of solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9
The zeros of solvefor m,A=3(m+3)^2-4(m-3)^2-42m+9 are m=-isqrt(A),m=isqrt(A)