What are the solutions to the equation solvefor x,z=x^2y+1 ?

The solutions to the equation solvefor x,z=x^2y+1 are x=sqrt((z-1)/y),x=-sqrt((z-1)/y);\quad y\ne 0

Find the zeros of solvefor x,z=x^2y+1

The zeros of solvefor x,z=x^2y+1 are x=sqrt((z-1)/y),x=-sqrt((z-1)/y);\quad y\ne 0

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solve for

x, z = x^{2} y + 1

x = \frac{z - 1}{y}, x = - \frac{z - 1}{y}; y \neq = 0

Solution steps

z = x^{2} y + 1

Switch sides

x^{2} y + 1 = z

Move

1

to the right side

x^{2} y = z - 1

Divide both sides by

y; y \neq = 0

x^{2} = \frac{z - 1}{y}; y \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{z - 1}{y}, x = - \frac{z - 1}{y}; y \neq = 0

A, A BX A - 1 B - 1 = I + A

(x + 3)^{2} - (x - 3)^{2} = x^{2} + 32

y, x^{3} + x y^{2} - y^{2} = 0

- 5 q^{2} + 9 q + 13 = - 6 q^{2}

y, x^{3} + x^{2} + 2 x y^{2} + 2 y^{2} - 4 x - 4 = 0

What are the solutions to the equation solvefor x,z=x^2y+1 ?
The solutions to the equation solvefor x,z=x^2y+1 are x=sqrt((z-1)/y),x=-sqrt((z-1)/y);\quad y\ne 0
Find the zeros of solvefor x,z=x^2y+1
The zeros of solvefor x,z=x^2y+1 are x=sqrt((z-1)/y),x=-sqrt((z-1)/y);\quad y\ne 0