What are the solutions to the equation p^2+13p-30=0 ?

The solutions to the equation p^2+13p-30=0 are p=2,p=-15

Find the zeros of p^2+13p-30=0

The zeros of p^2+13p-30=0 are p=2,p=-15

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p^{2} + 13 p - 30 = 0

p = 2, p = - 15

Solution steps

p^{2} + 13 p - 30 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 30) = 17

p_{1, 2} = \frac{- 13 \pm 17}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 13 + 17}{2 \cdot 1}, p_{2} = \frac{- 13 - 17}{2 \cdot 1}

p = \frac{- 13 + 17}{2 \cdot 1} : 2

p = \frac{- 13 - 17}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

p = 2, p = - 15

x^{2} + 4 a x - 12 a^{2} = 0

7^{2} + 2^{2} = c^{2}

x, y = - 0.00002 x^{2} + 0.0136 x + 0.1399

x, x^{2} + y^{2} = z^{2} (1 - z)

300 = 600 - 3 q^{2}

What are the solutions to the equation p^2+13p-30=0 ?
The solutions to the equation p^2+13p-30=0 are p=2,p=-15
Find the zeros of p^2+13p-30=0
The zeros of p^2+13p-30=0 are p=2,p=-15