What are the solutions to the equation 6x^2+18x+6=0 ?

The solutions to the equation 6x^2+18x+6=0 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2

Find the zeros of 6x^2+18x+6=0

The zeros of 6x^2+18x+6=0 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2

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6 x^{2} + 18 x + 6 = 0

x = \frac{- 3 + 5}{2}, x = - \frac{3 + 5}{2}

Decimal Notation

x = - 0.38196 \dots, x = - 2.61803 \dots

Solution steps

6 x^{2} + 18 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

1 8^{2} - 4 \cdot 6 \cdot 6 = 65

x_{1, 2} = \frac{- 18 \pm 6 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 18 + 6 5}{2 \cdot 6}, x_{2} = \frac{- 18 - 6 5}{2 \cdot 6}

x = \frac{- 18 + 6 5}{2 \cdot 6} : \frac{- 3 + 5}{2}

x = \frac{- 18 - 6 5}{2 \cdot 6} : - \frac{3 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{2}, x = - \frac{3 + 5}{2}

x, 16 x^{2} - 9 y^{2} - 64 x - 18 y + E = 0

A (x) = x^{2} + \frac{1.7}{4} (\frac{2}{3} - \frac{4}{3} x)^{2}

2 x^{2} - 180 x + 400 = 0

(2 x + 5) (3 x - 2) = (x + 1)

x^{2} + 10 x = - 15

What are the solutions to the equation 6x^2+18x+6=0 ?
The solutions to the equation 6x^2+18x+6=0 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2
Find the zeros of 6x^2+18x+6=0
The zeros of 6x^2+18x+6=0 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2