What are the solutions to the equation -x^2+5x+8=0 ?

The solutions to the equation -x^2+5x+8=0 are x=-(-5+sqrt(57))/2 ,x=(5+sqrt(57))/2

Find the zeros of -x^2+5x+8=0

The zeros of -x^2+5x+8=0 are x=-(-5+sqrt(57))/2 ,x=(5+sqrt(57))/2

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- x^{2} + 5 x + 8 = 0

x = - \frac{- 5 + 57}{2}, x = \frac{5 + 57}{2}

Decimal Notation

x = - 1.27491 \dots, x = 6.27491 \dots

Solution steps

- x^{2} + 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 8}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 8 = 57

x_{1, 2} = \frac{- 5 \pm 57}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 57}{2 ( - 1 )}, x_{2} = \frac{- 5 - 57}{2 ( - 1 )}

x = \frac{- 5 + 57}{2 ( - 1 )} : - \frac{- 5 + 57}{2}

x = \frac{- 5 - 57}{2 ( - 1 )} : \frac{5 + 57}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 57}{2}, x = \frac{5 + 57}{2}

c - c^{2} = \frac{1}{6}

x, 4 x y + x^{2} - 2 y^{2} = - 2

x^{2} - 16 x + 37 = 0

9 x^{2} - 19 x + 2 = 0

3 x - 7 x^{2} = 0

What are the solutions to the equation -x^2+5x+8=0 ?
The solutions to the equation -x^2+5x+8=0 are x=-(-5+sqrt(57))/2 ,x=(5+sqrt(57))/2
Find the zeros of -x^2+5x+8=0
The zeros of -x^2+5x+8=0 are x=-(-5+sqrt(57))/2 ,x=(5+sqrt(57))/2