What are the solutions to the equation 3x^2+x-24=0 ?

The solutions to the equation 3x^2+x-24=0 are x= 8/3 ,x=-3

Find the zeros of 3x^2+x-24=0

The zeros of 3x^2+x-24=0 are x= 8/3 ,x=-3

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3 x^{2} + x - 24 = 0

x = \frac{8}{3}, x = - 3

Decimal Notation

x = 2.66666 \dots, x = - 3

Solution steps

3 x^{2} + x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 24) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 3}, x_{2} = \frac{- 1 - 17}{2 \cdot 3}

x = \frac{- 1 + 17}{2 \cdot 3} : \frac{8}{3}

x = \frac{- 1 - 17}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - 3

100 + 60 x - 12 x^{2} = 0

\frac{a x ^{2}}{4} + \frac{x}{2} = \frac{2}{a}

x, 6 x^{2} = 7 x y + 20 y^{2}

5 x^{2} - x^{2} = 2 x^{2} + 72

x, x^{2} + y^{2} - 2 x + 2 y + 11 = 0

What are the solutions to the equation 3x^2+x-24=0 ?
The solutions to the equation 3x^2+x-24=0 are x= 8/3 ,x=-3
Find the zeros of 3x^2+x-24=0
The zeros of 3x^2+x-24=0 are x= 8/3 ,x=-3