What are the solutions to the equation completesquare x^2+6x-1=0 ?

The solutions to the equation completesquare x^2+6x-1=0 are x=sqrt(10)-3,x=-sqrt(10)-3

Find the zeros of completesquare x^2+6x-1=0

The zeros of completesquare x^2+6x-1=0 are x=sqrt(10)-3,x=-sqrt(10)-3

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x^{2} + 6 x - 1 = 0

x = 10 - 3, x = - 10 - 3

Decimal Notation

x = 0.16227 \dots, x = - 6.16227 \dots

Solution steps

x^{2} + 6 x - 1 = 0

Move

1

to the right side

x^{2} + 6 x = 1

Rewrite in the form

(x + a)^{2} = b

(x + 3)^{2} = 10

For

the solutions are

f (x) = a, - a

Solve

x + 3 = 10 : x = 10 - 3

Solve

x + 3 = - 10 : x = - 10 - 3

The solutions to the quadratic equation are:

x = 10 - 3, x = - 10 - 3

x, 2 x^{2} + 4 x y + 2 y^{2} - 5 x + 4 y + 7 = 0

x (12 - x) = 2 x^{2} - 8

16 y^{2} - 361 = 0

(x + 4) (x - 5) + 3 = 0

3 x^{2} - 12 + 9 = 0

What are the solutions to the equation completesquare x^2+6x-1=0 ?
The solutions to the equation completesquare x^2+6x-1=0 are x=sqrt(10)-3,x=-sqrt(10)-3
Find the zeros of completesquare x^2+6x-1=0
The zeros of completesquare x^2+6x-1=0 are x=sqrt(10)-3,x=-sqrt(10)-3