What are the solutions to the equation -x^2+4x=7 ?

The solutions to the equation -x^2+4x=7 are x=2-sqrt(3)i,x=2+sqrt(3)i

Find the zeros of -x^2+4x=7

The zeros of -x^2+4x=7 are x=2-sqrt(3)i,x=2+sqrt(3)i

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- x^{2} + 4 x = 7

x = 2 - 3 i, x = 2 + 3 i

Solution steps

- x^{2} + 4 x = 7

Move

7

to the left side

- x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) (- 7) : 23 i

x_{1, 2} = \frac{- 4 \pm 2 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 3 i}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 3 i}{2 ( - 1 )}

x = \frac{- 4 + 2 3 i}{2 ( - 1 )} : 2 - 3 i

x = \frac{- 4 - 2 3 i}{2 ( - 1 )} : 2 + 3 i

The solutions to the quadratic equation are:

x = 2 - 3 i, x = 2 + 3 i

x, x^{2} - 3 x y + 5 y^{2} - 28 x + 16 y - 30 = 0

- x^{2} + 64 = 0

0.8 x^{2} + 2 x + 2 = 0

x, y^{3} = 2 x^{2}

- x^{2} + 1 + 2 x (x + 3) = 8

What are the solutions to the equation -x^2+4x=7 ?
The solutions to the equation -x^2+4x=7 are x=2-sqrt(3)i,x=2+sqrt(3)i
Find the zeros of -x^2+4x=7
The zeros of -x^2+4x=7 are x=2-sqrt(3)i,x=2+sqrt(3)i