What are the solutions to the equation 10x^2+x-1=0 ?

The solutions to the equation 10x^2+x-1=0 are x=(-1+sqrt(41))/(20),x=(-1-sqrt(41))/(20)

Find the zeros of 10x^2+x-1=0

The zeros of 10x^2+x-1=0 are x=(-1+sqrt(41))/(20),x=(-1-sqrt(41))/(20)

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10 x^{2} + x - 1 = 0

x = \frac{- 1 + 41}{20}, x = \frac{- 1 - 41}{20}

Decimal Notation

x = 0.27015 \dots, x = - 0.37015 \dots

Solution steps

10 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 ( - 1 )}{2 \cdot 10}

1^{2} - 4 \cdot 10 (- 1) = 41

x_{1, 2} = \frac{- 1 \pm 41}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 41}{2 \cdot 10}, x_{2} = \frac{- 1 - 41}{2 \cdot 10}

x = \frac{- 1 + 41}{2 \cdot 10} : \frac{- 1 + 41}{20}

x = \frac{- 1 - 41}{2 \cdot 10} : \frac{- 1 - 41}{20}

The solutions to the quadratic equation are:

x = \frac{- 1 + 41}{20}, x = \frac{- 1 - 41}{20}

3 y^{2} - 108 = 0

x, z = \frac{( x ^{2} - y ^{2} )}{2}

2 x^{2} + x = 4 x - 2

- 4.9 t^{2} + 11.43 + 15 = 0

(x) = - x^{2} + 40 x - 300

What are the solutions to the equation 10x^2+x-1=0 ?
The solutions to the equation 10x^2+x-1=0 are x=(-1+sqrt(41))/(20),x=(-1-sqrt(41))/(20)
Find the zeros of 10x^2+x-1=0
The zeros of 10x^2+x-1=0 are x=(-1+sqrt(41))/(20),x=(-1-sqrt(41))/(20)