What are the solutions to the equation 2x^2+14x+20=216 ?

The solutions to the equation 2x^2+14x+20=216 are x=7,x=-14

Find the zeros of 2x^2+14x+20=216

The zeros of 2x^2+14x+20=216 are x=7,x=-14

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2 x^{2} + 14 x + 20 = 216

x = 7, x = - 14

Solution steps

2 x^{2} + 14 x + 20 = 216

Move

216

to the left side

2 x^{2} + 14 x - 196 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 2 ( - 196 )}{2 \cdot 2}

1 4^{2} - 4 \cdot 2 (- 196) = 42

x_{1, 2} = \frac{- 14 \pm 42}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 14 + 42}{2 \cdot 2}, x_{2} = \frac{- 14 - 42}{2 \cdot 2}

x = \frac{- 14 + 42}{2 \cdot 2} : 7

x = \frac{- 14 - 42}{2 \cdot 2} : - 14

The solutions to the quadratic equation are:

x = 7, x = - 14

5 x^{2} - 14 x + 9 = 0

x, y^{3} + y x^{2} + x^{2} - 3 y^{2} = 0

x, x^{2} y + 2 x y - x - 3 y + 3 = 0

x^{2} - 4 x - 60 = 0

y^{2} - 4 y + 40 = 0

What are the solutions to the equation 2x^2+14x+20=216 ?
The solutions to the equation 2x^2+14x+20=216 are x=7,x=-14
Find the zeros of 2x^2+14x+20=216
The zeros of 2x^2+14x+20=216 are x=7,x=-14