What are the solutions to the equation -x^2+9x+10=0 ?

The solutions to the equation -x^2+9x+10=0 are x=-1,x=10

Find the zeros of -x^2+9x+10=0

The zeros of -x^2+9x+10=0 are x=-1,x=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 9 x + 10 = 0

x = - 1, x = 10

Solution steps

- x^{2} + 9 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

9^{2} - 4 (- 1) \cdot 10 = 11

x_{1, 2} = \frac{- 9 \pm 11}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 11}{2 ( - 1 )}, x_{2} = \frac{- 9 - 11}{2 ( - 1 )}

x = \frac{- 9 + 11}{2 ( - 1 )} : - 1

x = \frac{- 9 - 11}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = - 1, x = 10

x^{2} + 8 x + 8 = \frac{( 0 ) - ( 0 )}{( 4 ) - ( - 3 )}

(- 1 - x) (1 - x) = 0

x, 9 x^{2} + 4 y^{2} + 36 x - 24 y + 216 = 0

0 = y^{2} - 4 y - 5

7^{2} = 4^{2} + b^{2}

What are the solutions to the equation -x^2+9x+10=0 ?
The solutions to the equation -x^2+9x+10=0 are x=-1,x=10
Find the zeros of -x^2+9x+10=0
The zeros of -x^2+9x+10=0 are x=-1,x=10