What are the solutions to the equation completesquare x^2+10x+22=0 ?

The solutions to the equation completesquare x^2+10x+22=0 are x=sqrt(3)-5,x=-sqrt(3)-5

Find the zeros of completesquare x^2+10x+22=0

The zeros of completesquare x^2+10x+22=0 are x=sqrt(3)-5,x=-sqrt(3)-5

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x^{2} + 10 x + 22 = 0

x = 3 - 5, x = - 3 - 5

Decimal Notation

x = - 3.26794 \dots, x = - 6.73205 \dots

Solution steps

x^{2} + 10 x + 22 = 0

Move

22

to the right side

x^{2} + 10 x = - 22

Rewrite in the form

(x + a)^{2} = b

(x + 5)^{2} = 3

For

the solutions are

f (x) = a, - a

Solve

x + 5 = 3 : x = 3 - 5

Solve

x + 5 = - 3 : x = - 3 - 5

The solutions to the quadratic equation are:

x = 3 - 5, x = - 3 - 5

3^{2} = 2^{2} + b^{2}

- 0.6 (x - 2.5)^{2} + 8.75 = 0

p^{2} - p - 1 = 0

- 55 = - 4 x^{2} + 6 x - 1

6 x^{2} - 2 x = 140

What are the solutions to the equation completesquare x^2+10x+22=0 ?
The solutions to the equation completesquare x^2+10x+22=0 are x=sqrt(3)-5,x=-sqrt(3)-5
Find the zeros of completesquare x^2+10x+22=0
The zeros of completesquare x^2+10x+22=0 are x=sqrt(3)-5,x=-sqrt(3)-5