What are the solutions to the equation 4x^2-37x+52=-8x+7 ?

The solutions to the equation 4x^2-37x+52=-8x+7 are x=5,x= 9/4

Find the zeros of 4x^2-37x+52=-8x+7

The zeros of 4x^2-37x+52=-8x+7 are x=5,x= 9/4

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4 x^{2} - 37 x + 52 = - 8 x + 7

x = 5, x = \frac{9}{4}

Decimal Notation

x = 5, x = 2.25

Solution steps

4 x^{2} - 37 x + 52 = - 8 x + 7

Move

7

to the left side

4 x^{2} - 37 x + 45 = - 8 x

Move

8 x

to the left side

4 x^{2} - 29 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 4 \cdot 45}{2 \cdot 4}

(- 29)^{2} - 4 \cdot 4 \cdot 45 = 11

x_{1, 2} = \frac{- ( - 29 ) \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 11}{2 \cdot 4}, x_{2} = \frac{- ( - 29 ) - 11}{2 \cdot 4}

x = \frac{- ( - 29 ) + 11}{2 \cdot 4} : 5

x = \frac{- ( - 29 ) - 11}{2 \cdot 4} : \frac{9}{4}

The solutions to the quadratic equation are:

x = 5, x = \frac{9}{4}

2 (s^{2} + 5 s + 6) = 0

x^{2} - 36 = - 9 x

0.3 + 0.08 x - 0.0012 x^{2} = 0

x (x + 6) + 2 x (x + 4) = x^{2} + 8

- 0.2 q^{2} + 80 = 4 q + 20

What are the solutions to the equation 4x^2-37x+52=-8x+7 ?
The solutions to the equation 4x^2-37x+52=-8x+7 are x=5,x= 9/4
Find the zeros of 4x^2-37x+52=-8x+7
The zeros of 4x^2-37x+52=-8x+7 are x=5,x= 9/4