What are the solutions to the equation 4p^2+4p+1=0 ?

The solutions to the equation 4p^2+4p+1=0 are p=-1/2

Find the zeros of 4p^2+4p+1=0

The zeros of 4p^2+4p+1=0 are p=-1/2

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4 p^{2} + 4 p + 1 = 0

p = - \frac{1}{2}

Decimal Notation

p = - 0.5

Solution steps

4 p^{2} + 4 p + 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

p_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

p = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

p = - \frac{1}{2}

The solution to the quadratic equation is:

p = - \frac{1}{2}

x^{2} + 12 x + 28 = 0

x^{2} - (2 + 2) x + 22 = 0

(x + 7) (x - 1) = 0

x^{2} + 5 - 24 = 0

2 x^{2} + x - 3 = x + 5

What are the solutions to the equation 4p^2+4p+1=0 ?
The solutions to the equation 4p^2+4p+1=0 are p=-1/2
Find the zeros of 4p^2+4p+1=0
The zeros of 4p^2+4p+1=0 are p=-1/2