What are the solutions to the equation x^2-3(2x+1)=0 ?

The solutions to the equation x^2-3(2x+1)=0 are x=3+2sqrt(3),x=3-2sqrt(3)

Find the zeros of x^2-3(2x+1)=0

The zeros of x^2-3(2x+1)=0 are x=3+2sqrt(3),x=3-2sqrt(3)

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x^{2} - 3 (2 x + 1) = 0

x = 3 + 23, x = 3 - 23

Decimal Notation

x = 6.46410 \dots, x = - 0.46410 \dots

Solution steps

x^{2} - 3 (2 x + 1) = 0

Expand

x^{2} - 3 (2 x + 1) : x^{2} - 6 x - 3

x^{2} - 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 3) = 43

x_{1, 2} = \frac{- ( - 6 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4 3}{2 \cdot 1} : 3 + 23

x = \frac{- ( - 6 ) - 4 3}{2 \cdot 1} : 3 - 23

The solutions to the quadratic equation are:

x = 3 + 23, x = 3 - 23

x^{2} + 2 x - 5 = 2

3902850 x^{2} - 6615000 x + 615475 = 0

3 x^{2} + 75 x = 0

n + \frac{n ( n - 3 )}{2} = 28

x, u = x^{2} - y^{2}

What are the solutions to the equation x^2-3(2x+1)=0 ?
The solutions to the equation x^2-3(2x+1)=0 are x=3+2sqrt(3),x=3-2sqrt(3)
Find the zeros of x^2-3(2x+1)=0
The zeros of x^2-3(2x+1)=0 are x=3+2sqrt(3),x=3-2sqrt(3)