What are the solutions to the equation 12x^2+6x-9=x-6 ?

The solutions to the equation 12x^2+6x-9=x-6 are x= 1/3 ,x=-3/4

Find the zeros of 12x^2+6x-9=x-6

The zeros of 12x^2+6x-9=x-6 are x= 1/3 ,x=-3/4

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12 x^{2} + 6 x - 9 = x - 6

x = \frac{1}{3}, x = - \frac{3}{4}

Decimal Notation

x = 0.33333 \dots, x = - 0.75

Solution steps

12 x^{2} + 6 x - 9 = x - 6

Move

6

to the left side

12 x^{2} + 6 x - 3 = x

Move

x

to the left side

12 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 12 ( - 3 )}{2 \cdot 12}

5^{2} - 4 \cdot 12 (- 3) = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 12}, x_{2} = \frac{- 5 - 13}{2 \cdot 12}

x = \frac{- 5 + 13}{2 \cdot 12} : \frac{1}{3}

x = \frac{- 5 - 13}{2 \cdot 12} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{4}

m^{2} + 4 m + 85 = 0

5 (\frac{1 + 3 y}{2})^{2} + 9 y^{2} = 6

3 x^{2} - 6 x - 9 = 0

- 3 x^{2} - x + 5 = 0

x, x^{2} y - 2 x y + y - x = 0

What are the solutions to the equation 12x^2+6x-9=x-6 ?
The solutions to the equation 12x^2+6x-9=x-6 are x= 1/3 ,x=-3/4
Find the zeros of 12x^2+6x-9=x-6
The zeros of 12x^2+6x-9=x-6 are x= 1/3 ,x=-3/4