What are the solutions to the equation -11x+6x^2=-3 ?

The solutions to the equation -11x+6x^2=-3 are x= 3/2 ,x= 1/3

Find the zeros of -11x+6x^2=-3

The zeros of -11x+6x^2=-3 are x= 3/2 ,x= 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 11 x + 6 x^{2} = - 3

x = \frac{3}{2}, x = \frac{1}{3}

Decimal Notation

x = 1.5, x = 0.33333 \dots

Solution steps

- 11 x + 6 x^{2} = - 3

Move

3

to the left side

- 11 x + 6 x^{2} + 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 11 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 \cdot 3 = 7

x_{1, 2} = \frac{- ( - 11 ) \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 7}{2 \cdot 6}, x_{2} = \frac{- ( - 11 ) - 7}{2 \cdot 6}

x = \frac{- ( - 11 ) + 7}{2 \cdot 6} : \frac{3}{2}

x = \frac{- ( - 11 ) - 7}{2 \cdot 6} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{3}

(5 x - 3)^{2} = - 3

5 x^{2} - 7 x - 18 = 0

X^{2} + 2 X - 1 = 0

x, x^{2} + y^{2} + z^{2} + 2 x - 6 y - 6 = 0

\frac{x ^{2}}{2} = 2 x

What are the solutions to the equation -11x+6x^2=-3 ?
The solutions to the equation -11x+6x^2=-3 are x= 3/2 ,x= 1/3
Find the zeros of -11x+6x^2=-3
The zeros of -11x+6x^2=-3 are x= 3/2 ,x= 1/3