What are the solutions to the equation 15x^2+96x-5760=0 ?

The solutions to the equation 15x^2+96x-5760=0 are x=(8(sqrt(154)-2))/5 ,x=-(8(2+sqrt(154)))/5

Find the zeros of 15x^2+96x-5760=0

The zeros of 15x^2+96x-5760=0 are x=(8(sqrt(154)-2))/5 ,x=-(8(2+sqrt(154)))/5

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15 x^{2} + 96 x - 5760 = 0

x = \frac{8 ( 154 - 2 )}{5}, x = - \frac{8 ( 2 + 154 )}{5}

Decimal Notation

x = 16.65547 \dots, x = - 23.05547 \dots

Solution steps

15 x^{2} + 96 x - 5760 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 \cdot 15 ( - 5760 )}{2 \cdot 15}

9 6^{2} - 4 \cdot 15 (- 5760) = 48154

x_{1, 2} = \frac{- 96 \pm 48 154}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 96 + 48 154}{2 \cdot 15}, x_{2} = \frac{- 96 - 48 154}{2 \cdot 15}

x = \frac{- 96 + 48 154}{2 \cdot 15} : \frac{8 ( 154 - 2 )}{5}

x = \frac{- 96 - 48 154}{2 \cdot 15} : - \frac{8 ( 2 + 154 )}{5}

The solutions to the quadratic equation are:

x = \frac{8 ( 154 - 2 )}{5}, x = - \frac{8 ( 2 + 154 )}{5}

2.5 x^{2} + 15 x - 120 = 0

- 0.25 x^{2} + 1500 = 83 x + 468

2 y = y^{2} - 3

x, x^{2} + 4 x - 32 = 0

- 2 x^{2} + 4 x + 48 = 0

What are the solutions to the equation 15x^2+96x-5760=0 ?
The solutions to the equation 15x^2+96x-5760=0 are x=(8(sqrt(154)-2))/5 ,x=-(8(2+sqrt(154)))/5
Find the zeros of 15x^2+96x-5760=0
The zeros of 15x^2+96x-5760=0 are x=(8(sqrt(154)-2))/5 ,x=-(8(2+sqrt(154)))/5