What are the solutions to the equation x^2-x-272=0 ?

The solutions to the equation x^2-x-272=0 are x=17,x=-16

Find the zeros of x^2-x-272=0

The zeros of x^2-x-272=0 are x=17,x=-16

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x^{2} - x - 272 = 0

x = 17, x = - 16

Solution steps

x^{2} - x - 272 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 272 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 272) = 33

x_{1, 2} = \frac{- ( - 1 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 33}{2 \cdot 1}

x = \frac{- ( - 1 ) + 33}{2 \cdot 1} : 17

x = \frac{- ( - 1 ) - 33}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 17, x = - 16

2 x^{2} + 22 x = - 48

6 x^{2} - 13 x + 3 = - 3

5 x^{2} - 28 x - 12 = 0

z^{2} + 6 z + 10 = 0

x^{2} + (2 k + 5) x + k = 0

What are the solutions to the equation x^2-x-272=0 ?
The solutions to the equation x^2-x-272=0 are x=17,x=-16
Find the zeros of x^2-x-272=0
The zeros of x^2-x-272=0 are x=17,x=-16