What are the solutions to the equation n^2-11n+18=0 ?

The solutions to the equation n^2-11n+18=0 are n=9,n=2

Find the zeros of n^2-11n+18=0

The zeros of n^2-11n+18=0 are n=9,n=2

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n^{2} - 11 n + 18 = 0

n = 9, n = 2

Solution steps

n^{2} - 11 n + 18 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 18 = 7

n_{1, 2} = \frac{- ( - 11 ) \pm 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 11 ) + 7}{2 \cdot 1}, n_{2} = \frac{- ( - 11 ) - 7}{2 \cdot 1}

n = \frac{- ( - 11 ) + 7}{2 \cdot 1} : 9

n = \frac{- ( - 11 ) - 7}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

n = 9, n = 2

x^{2} - 3 = 118

2 x^{2} + 4 = 5 x - 7, x^{2} + 2 = \frac{5}{2} x - \frac{7}{2}

2 x^{2} - 3 x + 4

t^{2} + 2 t + 1 = 0

x, z = y - x^{2} - 3 y^{2} + 1

What are the solutions to the equation n^2-11n+18=0 ?
The solutions to the equation n^2-11n+18=0 are n=9,n=2
Find the zeros of n^2-11n+18=0
The zeros of n^2-11n+18=0 are n=9,n=2