What are the solutions to the equation x(x+14)=-48 ?

The solutions to the equation x(x+14)=-48 are x=-6,x=-8

Find the zeros of x(x+14)=-48

The zeros of x(x+14)=-48 are x=-6,x=-8

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x (x + 14) = - 48

x = - 6, x = - 8

Solution steps

x (x + 14) = - 48

Expand

x (x + 14) : x^{2} + 14 x

x^{2} + 14 x = - 48

Move

48

to the left side

x^{2} + 14 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 48 = 2

x_{1, 2} = \frac{- 14 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2}{2 \cdot 1}, x_{2} = \frac{- 14 - 2}{2 \cdot 1}

x = \frac{- 14 + 2}{2 \cdot 1} : - 6

x = \frac{- 14 - 2}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 6, x = - 8

4^{2} + 1 0^{2} = c^{2}

x, x^{2} + y^{2} = 2 z

- 3 x^{2} + 4 x + 3 = 0

a, a (a - b) = 31

80 + 40 t - 4.9 t^{2} = 0

What are the solutions to the equation x(x+14)=-48 ?
The solutions to the equation x(x+14)=-48 are x=-6,x=-8
Find the zeros of x(x+14)=-48
The zeros of x(x+14)=-48 are x=-6,x=-8