What are the solutions to the equation 5z-2(z^2+1)=0 ?

The solutions to the equation 5z-2(z^2+1)=0 are z= 1/2 ,z=2

Find the zeros of 5z-2(z^2+1)=0

The zeros of 5z-2(z^2+1)=0 are z= 1/2 ,z=2

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5 z - 2 (z^{2} + 1) = 0

z = \frac{1}{2}, z = 2

Decimal Notation

z = 0.5, z = 2

Solution steps

5 z - 2 (z^{2} + 1) = 0

Expand

5 z - 2 (z^{2} + 1) : 5 z - 2 z^{2} - 2

5 z - 2 z^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 z^{2} + 5 z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

5^{2} - 4 (- 2) (- 2) = 3

z_{1, 2} = \frac{- 5 \pm 3}{2 ( - 2 )}

Separate the solutions

z_{1} = \frac{- 5 + 3}{2 ( - 2 )}, z_{2} = \frac{- 5 - 3}{2 ( - 2 )}

z = \frac{- 5 + 3}{2 ( - 2 )} : \frac{1}{2}

z = \frac{- 5 - 3}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

z = \frac{1}{2}, z = 2

z^{2} - 4 z + 4

x, \frac{x ^{2}}{1.62} = 5.56 \cdot 1 0^{- 10}

x, 6 x^{2} + 9 y^{2} - 24 x - 54 y + 105 = 0

x^{2} + 5 \cdot x + 6 = 0

3 x^{2} + x = - 1

What are the solutions to the equation 5z-2(z^2+1)=0 ?
The solutions to the equation 5z-2(z^2+1)=0 are z= 1/2 ,z=2
Find the zeros of 5z-2(z^2+1)=0
The zeros of 5z-2(z^2+1)=0 are z= 1/2 ,z=2