What are the solutions to the equation 7=3(x-3)^2+4 ?

The solutions to the equation 7=3(x-3)^2+4 are x=4,x=2

Find the zeros of 7=3(x-3)^2+4

The zeros of 7=3(x-3)^2+4 are x=4,x=2

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7 = 3 (x - 3)^{2} + 4

x = 4, x = 2

Solution steps

7 = 3 (x - 3)^{2} + 4

Switch sides

3 (x - 3)^{2} + 4 = 7

Move

4

to the right side

3 (x - 3)^{2} = 3

Divide both sides by

3

(x - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 1 : x = 4

Solve

x - 3 = - 1 : x = 2

The solutions to the quadratic equation are:

x = 4, x = 2

lo g_{3} (6 x)

(\frac{1}{8})^{- \frac{1}{3}}

- 45 > - 5 n

8 x^{2} - 10 x - \frac{3 x ^{2}}{7} - 43 x = 0

(\frac{1}{10})^{6}

What are the solutions to the equation 7=3(x-3)^2+4 ?
The solutions to the equation 7=3(x-3)^2+4 are x=4,x=2
Find the zeros of 7=3(x-3)^2+4
The zeros of 7=3(x-3)^2+4 are x=4,x=2