What are the solutions to the equation -2y^2+30y=0 ?

The solutions to the equation -2y^2+30y=0 are y=0,y=15

Find the zeros of -2y^2+30y=0

The zeros of -2y^2+30y=0 are y=0,y=15

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- 2 y^{2} + 30 y = 0

y = 0, y = 15

Solution steps

- 2 y^{2} + 30 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

3 0^{2} - 4 (- 2) \cdot 0 = 30

y_{1, 2} = \frac{- 30 \pm 30}{2 ( - 2 )}

Separate the solutions

y_{1} = \frac{- 30 + 30}{2 ( - 2 )}, y_{2} = \frac{- 30 - 30}{2 ( - 2 )}

y = \frac{- 30 + 30}{2 ( - 2 )} : 0

y = \frac{- 30 - 30}{2 ( - 2 )} : 15

The solutions to the quadratic equation are:

y = 0, y = 15

- x^{2} + 4 x = - 12

C (t) = - 0.0002 t^{2} + 0.06 t, 0 \leq t \leq 240

110.25 - 17.5 y + 7 y^{2} = 120

x, x^{2} + 4 y^{2} + z^{2} = 9

5 - 11 x^{2} = - 8 x

What are the solutions to the equation -2y^2+30y=0 ?
The solutions to the equation -2y^2+30y=0 are y=0,y=15
Find the zeros of -2y^2+30y=0
The zeros of -2y^2+30y=0 are y=0,y=15